A) True
B) False
C) Can't say
D) Partially True/False
Correct Answer: B
Solution :
We know that, the points lies on perpendicular bisector of the line segment joining the two points is equidistant from these two points. |
\[\therefore \,\,PA=\sqrt{{{\left( -1-0 \right)}^{2}}+{{\left( 1-2 \right)}^{2}}}\] |
\[=\sqrt{1+1}=\sqrt{2}\]units |
\[PB=\sqrt{{{\left( 3-0 \right)}^{2}}+{{\left( 3-2 \right)}^{2}}}=\sqrt{9+1}=10\]units |
\[\because \,\,\,PA\ne PB\] |
So, the point P does not lie on the perpendicular bisctor of AB. |
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