A) right triangle
B) isosceles triangle
C) equilateral triangle
D) scalene triangle
Correct Answer: B
Solution :
| [b] Let \[A(-4,0),\] \[B(4,0),\] \[C(0,3)\]are the given vertices. |
| Now, distance between \[A(-4,0)\] and \[B(4,0)\] |
| \[AB=\sqrt{{{[4-(-4)]}^{2}}+{{(0-0)}^{2}}}=\sqrt{{{(4+4)}^{2}}}=\sqrt{{{8}^{2}}}=8\]Distance between \[B(4,0)\] and \[C(0,3)\] |
| \[BC=\sqrt{{{(0-4)}^{2}}+{{(3-0)}^{2}}}=\sqrt{16+9}=\sqrt{25}=5\] |
| Distance between \[A(-4,0)\] and \[C(0,3)\]. |
| \[AC=\sqrt{[0-{{(-4)}^{2}}]+{{(3-0)}^{2}}}=\sqrt{16+9}=\sqrt{25}=5\] \[BC=AC\] |
| Hence, \[\Delta ABC\] is an isosceles triangle because an isosceles triangle has two sides equal. |
You need to login to perform this action.
You will be redirected in
3 sec