A) \[50\,sq.\,units\]
B) \[45\,sq.\,units\]
C) \[40\,sq.\,units\]
D) \[30\,sq.\,units\]
Correct Answer: C
Solution :
[c] Let \[A(0,-1),\]\[B(6,7),\]\[C(-2,3)\] and \[D(8,3)\] be the given vertices of a rectangle. Then, |
\[AD=\sqrt{{{(8-0)}^{2}}+{{(3+1)}^{2}}}=\sqrt{64+16}=4\sqrt{5}\] |
and \[AC=\sqrt{{{(-2-0)}^{2}}+{{(3+1)}^{2}}}=\sqrt{4+16}=2\sqrt{5}\] |
\[\therefore \] Area of rectangle \[ADBC=AD\times AC\] |
\[=4\sqrt{5}\times 2\sqrt{5}=40\,\,sq.\] units. |
You need to login to perform this action.
You will be redirected in
3 sec