A) \[12\]
B) \[5\]
C) \[13\]
D) \[169\]
Correct Answer: C
Solution :
| [c] Required distance \[=\sqrt{{{(0+12)}^{2}}+{{(0-5)}^{2}}}\] |
| \[=\sqrt{144+25}=\sqrt{169}=13\] |
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