A) 5
B) 6
C) 2
D) 4
Correct Answer: C
Solution :
[c] Since A and B lie on the circle having centre O. |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,OA=OB\] (Each equal to radius] |
\[\Rightarrow \,\,\,\,\sqrt{{{(4-2)}^{2}}+{{(3-3)}^{2}}}=\sqrt{{{(x-2)}^{2}}+{{(5-3)}^{2}}}\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2=\sqrt{{{(x-2)}^{2}}+4}\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,4={{(x-2)}^{2}}+4\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{(x-2)}^{2}}=0\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x-2=0\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x=2\] |
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