A) isosceles triangle
B) equilateral triangle
C) right angled triangle
D) None of these
Correct Answer: D
Solution :
[d] Let \[A(2,5),\] \[B(4,-1)\]and \[C(6,-2)\] |
\[AB=\sqrt{{{(4-2)}^{2}}+{{(-1-5)}^{2}}}=\sqrt{40}\] |
\[BC=\sqrt{{{(6-4)}^{2}}+{{(-7+1)}^{2}}}=\sqrt{40}\] |
\[AC=\sqrt{{{(6-2)}^{2}}+{{(-7-5)}^{2}}}=\sqrt{160}=2\sqrt{40}\] |
\[\therefore \,\,\,\,AB+BC=AC\] |
Here\[AB+BC=AC\] |
\[\therefore \] A, B and Care coilinear. |
You need to login to perform this action.
You will be redirected in
3 sec