A) \[1:4\]
B) \[4:1\]
C) \[1:2\]
D) \[2:1\]
Correct Answer: B
Solution :
| [b] Mid-point of AC = mid-point of BD |
| Let \[A(-3-1),\,B(a,b),\,C(3,3),\,D(4,3)\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(0,1)=\left( \frac{4+a}{2},\,\,\frac{3+b}{2} \right)\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,a=-4,\,\,b=-1\] |
| \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,a:b=4:1\] |
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