A) source of emf.
B) electric field produced by charges accumulated on the surface of wire.
C) the charges just behind a given segment of Wire which push them just the right way by repulsion.
D) the charges ahead.
Correct Answer: B
Solution :
| Option [b] is correct |
| Explanation: As we know that current density |
| (I) depends on |
| (i) conductivity [\[\sigma \] = 1/ p = 1/ R.A] |
| (ii) Electric field [J = \[\sigma \]E] |
| (iii) current, length and area of cross-section |
| But in the given options only B, that is, electric field can be varied by the charges accumulated on the surface of wire. |
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