12th Class Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank MCQs - Current Electricity

  • question_answer
    When cell of e.m.f. E is connected with an external resistance R, the p.d. across the cell becomes V. The expression for the internal resistance of the cell is

    A) \[\frac{E\ -V}{V}R\]

    B) \[{{10}^{23}}\]

    C) \[\frac{V-E}{V}R\]

    D) \[\frac{V-E}{\operatorname{E}}R\]

    Correct Answer: A

    Solution :

    Option [a] is correct.
    Explanation: Current in the circuit = I = V /R If r = internal resistance of the cell, then
    V=E - Ir
     \[\therefore \operatorname{r}=\frac{E\ -V}{I}=\frac{E\ -V}{V/R}=\frac{E\ -V}{V}R\]


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