A) 1.2 nm
B) 1.2\[\times {{10}^{-3}}\]nm
C) 1.2 \[\times {{10}^{-6}}\] nm
D) 1.2 \[\times \] 10 nm
Correct Answer: B
Solution :
| Option [b] is correct. |
| Explanation: Energy of the photon must be equal to the binding energy of proton |
| So, energy of photon = 1 MeV |
| \[={{10}^{6}}\times 1.6\times {{10}^{19}}\operatorname{J}\] |
| \[\lambda =\frac{hc}{\operatorname{E}}=\frac{6.63\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.6\times {{10}^{-13}}}=\frac{6.63\times 3}{1.60}\times {{10}^{-26+13}}\]\[=\frac{19.89}{1.60}\times {{10}^{-13}}=12.4\times {{10}^{-13}}=1.24\times {{10}^{1}}\times {{10}^{-13}}\]\[=12.4\times {{10}^{-9}}\times {{10}^{-3}}=1.24\times {{10}^{-3}}\]nm |
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