A) H
B) \[{{\operatorname{H}}^{1/2}}\]
C) \[{{\operatorname{H}}^{o}}\]
D) \[{{\operatorname{H}}^{-1/2}}\]
Correct Answer: D
Solution :
| Option [d] is correct. |
| Explanation: Velocity v, of freely falling body after falling from a height H, will be : \[\operatorname{H}=v=\sqrt{2gH}\] |
| We know that de-Broglie wavelength, \[\lambda =\frac{h}{p}\] |
| \[\lambda =\frac{h}{mv}=\frac{h}{m\sqrt{2gH}}\] |
| h, m, and g are constant |
| \[\therefore \frac{h}{m\sqrt{2g}}\operatorname{is} constant\Rightarrow \lambda \propto \frac{1}{\sqrt{H}}\Rightarrow \lambda \propto {{\operatorname{H}}^{-1/2}}\] |
You need to login to perform this action.
You will be redirected in
3 sec
