A) \[{{\operatorname{Li}}^{2}}\]
B) \[\frac{1}{2}\operatorname{Li}\]
C) \[\operatorname{Li}\]
D) \[\frac{1}{2}{{\operatorname{Li}}^{2}}\]
Correct Answer: D
Solution :
Option [d] is correct. Explanation: If current I flows through a coil of self-inductance L, then magnetic field energy stored in it is \[\frac{1}{2}{{\operatorname{Li}}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
