A) spheres.
B) planes
C) paraboloids.
D) ellipsoids.
Correct Answer: A
Solution :
| Option [a] is correct. |
| Explanation: For equipotential surface, these surfaces are perpendicular to the field lines. |
| So there must be electric field, which cannot be without charge. |
| So the algebraic sum of all charges must not be zero. Equipotential surface at a great distance means that space of charge is negligible as compared to distance. So the collection of charges is considered as a point charge. |
| Electric potential due to point charge is, |
| \[V={{k}_{e}}\frac{q}{r}\] |
| which explains that electric potentials due to point charge is same for all equidistant points. |
| The locus of these equidistant points, which are at same potential, forms spherical surface. |
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