A) \[2\times {{10}^{3}}\operatorname{N}\]
B) \[2\times {{10}^{4}}\operatorname{N}\]
C) \[2\times {{10}^{6}}\operatorname{N}\]
D) \[2\times {{10}^{5}}\operatorname{N}\]
Correct Answer: B
Solution :
| [b] Given, u = 200 m/s, v = 0, s = 0.02 m and |
| m = 20 g = 20 \[\times \] \[{{10}^{-3}}\] kg |
| From third equation of motion, |
| \[{{v}^{2}}={{u}^{2}}+2as\Rightarrow a\frac{{{v}^{2}}-{{u}^{2}}}{2s}\] |
| Negative sign indicates retardation |
| \[\therefore \] Resistive force, F=ma |
| =\[20\times {{10}^{-3}}\times {{10}^{6}}\] |
| = \[2\times {{10}^{4}}\]N |
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