A) \[{{C}_{2}}{{H}_{5}}F>{{C}_{2}}{{H}_{5}}Cl>{{C}_{2}}{{H}_{5}}Br>{{C}_{2}}{{H}_{5}}I\]
B) \[{{C}_{2}}{{H}_{5}}I>{{C}_{2}}{{H}_{5}}Br>{{C}_{2}}{{H}_{5}}Cl>{{C}_{2}}{{H}_{5}}F\]
C) \[{{C}_{2}}{{H}_{5}}I>{{C}_{2}}{{H}_{5}}Cl>{{C}_{2}}{{H}_{5}}Br>{{C}_{2}}{{H}_{5}}F\]
D) \[{{C}_{2}}{{H}_{5}}F>{{C}_{2}}{{H}_{5}}I>{{C}_{2}}{{H}_{5}}Br>{{C}_{2}}{{H}_{5}}Cl\]
Correct Answer: B
Solution :
The reactivity order can be explained on the basis of C-X bond strength. Lower the bond strength, higher is the reactivity.You need to login to perform this action.
You will be redirected in
3 sec