A) 1-butene
B) 2-butane
C) 1-butanol
D) 2-butanol
Correct Answer: A
Solution :
[a]\[\underset{1\,-\,chlorobu\operatorname{tane}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}}}\,Cl+\underset{(Alc.)}{\mathop{KOH}}\,\to \underset{1-butene}{\mathop{C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}}}\,+KCl+{{H}_{2}}O\] |
When 1-chlorobutane is treated with alc. KOH, then 1-butene gets formed along with KCl and water. |
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