| Decreasing order of reactivity of HX in the following reaction |
| \[ROH+HX\to RX+{{H}_{2}}O\] |
A) \[HI>HBr>HC1>HF\]
B) \[HBr>HC1>HI>HF\]
C) \[HC1>HBr>HI>HF\]
D) \[HF>HBr>HC1>HI\]
Correct Answer: A
Solution :
[a]| \[Hl>HBr>HCl>HF\] |
| This order is based on strong nucleophilicity. As electronegativity increases, nucleophilicity decreases. |
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