A) alcoholic KOH
B) aqueous KOH
C) water
D) aqueous \[KMn{{O}_{4}}\]
Correct Answer: B
Solution :
\[{{C}_{2}}{{H}_{5}}Br+KO{{H}_{(aq)}}\to {{C}_{2}}{{H}_{5}}OH+KCl\]You need to login to perform this action.
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