A) \[{{C}_{2}}{{H}_{4}}+HBr\]
B) \[{{C}_{3}}{{H}_{6}}+C{{l}_{2}}\]
C) \[{{C}_{3}}{{H}_{6}}+HBr\]
D) \[{{C}_{3}}{{H}_{6}}+B{{r}_{2}}\]
Correct Answer: C
Solution :
Markovnikov's rule is followed for addition of HX on asymmetric alkenes. \[C{{H}_{3}}CH=C{{H}_{2}}+HBr\to \]You need to login to perform this action.
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