A) \[0\]
B) \[1\]
C) \[\sqrt{3}\]
D) \[\infty \]
Correct Answer: B
Solution :
[b] Given, \[\sin A=\frac{1}{2}=\sin 30{}^\circ \] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,A=30{}^\circ \] |
and\[\cos B=\frac{1}{2}=\cos 60{}^\circ \] |
\[\Rightarrow \,\,\,\,\,\,\,\,B=60{}^\circ \] |
\[\therefore \,\,\,\,\,\,\tan \frac{1}{2}(A+B)=\tan \frac{1}{2}(30{}^\circ +60{}^\circ )=\tan 45{}^\circ =1\] |
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