A) 1
B) 9
C) 8
D) 0
Correct Answer: B
Solution :
[b] \[9{{\sec }^{2}}A-9{{\tan }^{2}}A=9({{\sec }^{2}}A-{{\tan }^{2}}A)\] |
\[=9\times 1=9\]\[[{{\sec }^{2}}\theta -{{\tan }^{2}}\theta =1]\] |
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