A) \[0\]
B) \[1\]
C) \[-1\]
D) \[10\]
Correct Answer: D
Solution :
| [d]\[(\tan \theta +2)(2\tan \theta +1)=2{{\tan }^{2}}\theta +5\tan \theta +2\] |
| \[=2({{\sec }^{2}}\theta -1)+5\tan \theta +2\] |
| \[=5\tan \theta +2{{\sec }^{2}}\theta =A\tan \theta +B{{\sec }^{2}}\theta \] |
| On comparing, we get |
| \[A=5\] and \[B=2\] |
| \[\therefore \,\,\,\,\,\,\,\,\,\,\,AB=5\times 2=10\] |
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