A) \[0\]
B) \[1\]
C) \[-1\]
D) \[10\]
Correct Answer: D
Solution :
[d]\[(\tan \theta +2)(2\tan \theta +1)=2{{\tan }^{2}}\theta +5\tan \theta +2\] |
\[=2({{\sec }^{2}}\theta -1)+5\tan \theta +2\] |
\[=5\tan \theta +2{{\sec }^{2}}\theta =A\tan \theta +B{{\sec }^{2}}\theta \] |
On comparing, we get |
\[A=5\] and \[B=2\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,AB=5\times 2=10\] |
You need to login to perform this action.
You will be redirected in
3 sec