A) \[\sin \theta -\cos \theta \]
B) \[\cos \theta -\sin \theta \]
C) \[\cos \theta +\sin \theta \]
D) \[\sin \theta \,\cos \theta \]
Correct Answer: B
Solution :
| [b] \[\sqrt{1-2\sin \theta \cos \theta }=\sqrt{{{\sin }^{2}}\theta +{{\cos }^{2}}\theta -2\sin \theta \cos \theta }\]\[=\sqrt{{{(cos\theta -sin\theta )}^{2}}}\] |
| \[[{{a}^{2}}+{{b}^{2}}-2ab={{(a-b)}^{2}}and1=si{{n}^{2}}\theta +{{\cos }^{2}}\theta ]\] |
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