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10th Class Mathematics Introduction to Trigonometry Question Bank MCQs - Introduction to Trigonometry

  • question_answer
    The value of \[(\text{cose}{{\text{c}}^{2}}\theta -1){{\tan }^{2}}\theta \] is:                  (CBSE 2016)

    A) \[-1\]

    B) \[1\]

    C) \[\cot \theta \]

    D) \[\sec \theta \]

    Correct Answer: B

    Solution :

    [b] \[({{\operatorname{cosec}}^{2}}\theta -1)ta{{n}^{2}}\theta ={{\cot }^{2}}\theta \cdot {{\tan }^{2}}\theta ={{\cot }^{2}}\theta \frac{1}{{{\cot }^{2}}\theta }=1\]
    \[\left( \cos e{{c}^{2}}\theta -1={{\cot }^{2}}\theta and\tan \theta =\frac{1}{\cot \theta } \right)\]


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