A) \[\tan A-\cot A\]
B) \[\frac{tan\,A}{\sec A}\]
C) \[\tan A-\sec A\]
D) \[\cos A-\sec A\]
Correct Answer: B
Solution :
[b] \[\frac{\tan A}{\sec A}=\frac{\sin A/\cos A}{1/\cos A}=\sin A\]
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