10th Class Mathematics Introduction to Trigonometry Question Bank MCQs - Introduction to Trigonometry

  • question_answer
    If \[\text{sin x}+\text{cosec x}=\text{2},\]then \[{{\sin }^{19}}x+\text{cose}{{\text{c}}^{20}}x=\]

    A) \[{{2}^{19}}\]

    B) \[{{2}^{20}}\]

    C) \[2\]

    D) \[{{2}^{39}}\]

    Correct Answer: C

    Solution :

    [c]\[\sin x+\cos ec\,\,\,\,x=2\]
    \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\sin x+\frac{1}{\sin x}=2\,\,\,\,\,\,\,\,\Rightarrow \,\,\,\,{{\sin }^{2}}x+1=2\sin x\]
    \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,{{(\sin x-1)}^{2}}=0\,\,\,\,\,\Rightarrow \,\,\,\,\,\,\,\sin x=1\]
    \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\cos ec\,\,x=1\]
    \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,{{\sin }^{19}}x+\cos e{{c}^{20}}x=1+1=2\]


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