A) 196
B) 194
C) 192
D) 190
Correct Answer: B
Solution :
[b] \[{{(\tan A+\cot A)}^{2}}={{4}^{2}}\] |
\[\Rightarrow \,\,\,\,\,\,\,\,{{\tan }^{2}}A+{{\cot }^{2}}A+2=16\] |
\[\Rightarrow \,\,\,\,\,\,\,\,{{\tan }^{2}}A+{{\cot }^{2}}A=14\] |
\[\Rightarrow \,\,\,\,\,\,\,\,{{({{\tan }^{2}}A+{{\cot }^{2}}A)}^{2}}={{(14)}^{2}}\] |
\[\Rightarrow \,\,\,\,\,\,\,\,{{\tan }^{4}}A+{{\cot }^{4}}A+2=196\] |
\[\Rightarrow \,\,\,\,\,\,\,\,{{\tan }^{4}}A+{{\cot }^{4}}A=194\] |
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