| In \[\Delta ABC,\] \[\angle B=90{}^\circ ,\] \[\angle A=30{}^\circ \]and \[AB=9\,cm\]. Then, \[BC=\] |
 |
A) \[3cm\]
B) \[2\sqrt{3}cm\]
C) \[3\sqrt{3}cm\]
D) \[6\,cm\]
Correct Answer: C
Solution :
| [c] We have, \[\tan 30{}^\circ =\frac{BC}{AB}=\frac{1}{\sqrt{3}}\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\frac{BC}{9}=\frac{1}{\sqrt{3}}\] [Given, \[AB=9\,cm\]] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,BC=\left( 9\times \frac{1}{\sqrt{3}} \right)cm=3\sqrt{3}cm\] |
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