A) \[60{}^\circ \]
B) \[45{}^\circ \]
C) \[30{}^\circ \]
D) \[15{}^\circ \]
Correct Answer: D
Solution :
| [d] We have, \[\sin 2A=\frac{1}{2}{{\tan }^{2}}45{}^\circ \] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\sin 2A=\frac{1}{2}{{(1)}^{2}}=\frac{1}{2}\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2A=30{}^\circ \] \[\left[ \sin 30{}^\circ =\frac{1}{2} \right]\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,A=15{}^\circ \] |
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