A) \[{{2}^{19}}\]
B) \[{{2}^{20}}\]
C) \[2\]
D) \[{{2}^{39}}\]
Correct Answer: C
Solution :
[c]\[\sin x+\cos ec\,\,\,\,x=2\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\sin x+\frac{1}{\sin x}=2\,\,\,\,\,\,\,\,\Rightarrow \,\,\,\,{{\sin }^{2}}x+1=2\sin x\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,{{(\sin x-1)}^{2}}=0\,\,\,\,\,\Rightarrow \,\,\,\,\,\,\,\sin x=1\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\cos ec\,\,x=1\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,{{\sin }^{19}}x+\cos e{{c}^{20}}x=1+1=2\] |
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