A) 1
B) 0
C) 2
D) None of these
Correct Answer: A
Solution :
We know that, \[{{\sin }^{2}}A+{{\cos }^{2}}A=1\] \[1+{{\cos }^{2}}A=1\] \[{{\cos }^{2}}A=0\] \[{{\sin }^{2}}A-{{\cos }^{2}}A=1-0=1\]You need to login to perform this action.
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