A) \[\frac{1}{\sqrt{2}}\]
B) \[\sqrt{2}\]
C) \[\frac{\sqrt{3}}{2}\]
D) \[1\]
Correct Answer: B
Solution :
[b] \[\sin 45{}^\circ +\cos 45{}^\circ =\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}=\frac{2}{\sqrt{2}}=\sqrt{2}\]
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