A) \[\sin 60{}^\circ \]
B) \[\cos 60{}^\circ \]
C) \[\tan 60{}^\circ \]
D) \[\sin 30{}^\circ \]
Correct Answer: A
Solution :
[a] \[\frac{2\tan 30{}^\circ }{1+\tan 30{}^\circ }=\frac{2\times \frac{1}{\sqrt{3}}}{1+{{\left( \frac{1}{\sqrt{3}} \right)}^{2}}}=\frac{2/\sqrt{3}}{1+\frac{1}{3}}=\frac{2}{\sqrt{3}}\times \frac{3}{4}=\frac{\sqrt{3}}{2}=\sin 60{}^\circ \]
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