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10th Class Mathematics Introduction to Trigonometry Question Bank MCQs - Introduction to Trigonometry

  • question_answer
    \[\frac{1-{{\tan }^{2}}45{}^\circ }{1+{{\tan }^{2}}45{}^\circ }\]is equal to:  (NCERT EXEMPLAR)

    A) \[\tan 90{}^\circ \]

    B) \[1\]

    C) \[sin45{}^\circ \]

    D) 0

    Correct Answer: D

    Solution :

    [d] \[\frac{1-{{\tan }^{2}}45{}^\circ }{1+{{\tan }^{2}}45{}^\circ }=\frac{1-{{(1)}^{2}}}{1+{{(1)}^{2}}}=\frac{1-1}{1+1}=\frac{0}{2}=0\]


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