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10th Class Mathematics Introduction to Trigonometry Question Bank MCQs - Introduction to Trigonometry

  • question_answer
    The value of \[\frac{1-{{\cot }^{2}}45{}^\circ }{1+{{\sin }^{2}}45{}^\circ }.10\]is:

    A) \[1\]

    B) \[-1\]

    C) \[0\]

    D) \[10\]

    Correct Answer: C

    Solution :

    [c] \[10\cdot \frac{1-{{\cot }^{2}}45{}^\circ }{1+{{\sin }^{2}}45{}^\circ }=10\cdot \frac{1-{{(1)}^{2}}}{1+{{\left( \frac{1}{\sqrt{2}} \right)}^{2}}}=10\cdot \frac{1-1}{1+\frac{1}{2}}\]
    \[[\,\therefore \,\,\,\,\,\cot 45{}^\circ =\sin 90{}^\circ =1]\]
    \[=10\cdot \frac{0}{3/2}=10\times 0=0\]


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