A) \[-\frac{1}{2}\]
B) \[\frac{\sqrt{3}}{2}\]
C) \[\frac{3}{2}\]
D) \[\frac{2}{3}\]
Correct Answer: A
Solution :
[a] \[{{\sin }^{2}}30{}^\circ -{{\cos }^{2}}30{}^\circ ={{\left( \frac{1}{2} \right)}^{2}}-{{\left( \frac{\sqrt{3}}{2} \right)}^{2}}\] |
\[=\frac{1}{4}-\frac{3}{4}=\frac{-2}{4}=\frac{-1}{2}\] |
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