A) \[\sin 60{}^\circ \]
B) \[\cos 60{}^\circ \]
C) \[\tan 60{}^\circ \]
D) \[\sec 60{}^\circ \]
Correct Answer: B
Solution :
| [b] \[2{{\cos }^{2}}30{}^\circ -1=2\times {{\left( \frac{\sqrt{3}}{2} \right)}^{2}}-1\] |
| \[=\frac{3}{2}-1=\frac{1}{2}=cos60{}^\circ \] |
You need to login to perform this action.
You will be redirected in
3 sec
