A) \[\frac{2\cos 30{}^\circ }{1-{{\cos }^{2}}30{}^\circ }\]
B) \[\frac{2\tan 30{}^\circ }{1-{{\tan }^{2}}30{}^\circ }\]
C) \[\frac{2\cot 30{}^\circ }{1-{{\cot }^{2}}30{}^\circ }\]
D) \[2\,\sin 60{}^\circ \]
Correct Answer: B
Solution :
| [b] On verification, \[\frac{2\tan 30{}^\circ }{1-{{\tan }^{2}}30{}^\circ }=\frac{2\times \frac{1}{\sqrt{3}}}{1-\frac{1}{3}}=\sqrt{3}\] |
| \[=\tan 60{}^\circ \] |
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