A) \[\frac{1}{\cot A}\]
B) \[\frac{1}{\text{cosec}A}\]
C) \[\frac{1}{\sqrt{1+{{\cot }^{2}}A}}\]
D) \[\frac{\sqrt{1+{{\cot }^{2}}A}}{\cot A}\]
Correct Answer: D
Solution :
[d]\[\sec A=\frac{1}{\cos A}=\frac{\frac{1}{\sin A}}{\frac{\cos A}{\sin A}}=\frac{\cos ec\,\,A}{\cot A}=\frac{\sqrt{1+{{\cot }^{2}}A}}{\cot A}\]You need to login to perform this action.
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