10th Class Mathematics Introduction to Trigonometry Question Bank MCQs - Introduction to Trigonometry

  • question_answer
    \[9{{\sec }^{2}}A-9{{\tan }^{2}}A\]is equal to: (NCERT EXEMPLAR)

    A) 1

    B) 9

    C) 8

    D) 0

    Correct Answer: B

    Solution :

    [b] \[9{{\sec }^{2}}A-9{{\tan }^{2}}A=9({{\sec }^{2}}A-{{\tan }^{2}}A)\]
    \[=9\times 1=9\]\[[{{\sec }^{2}}\theta -{{\tan }^{2}}\theta =1]\]


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