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  5. Introduction to Trigonometry

10th Class Mathematics Introduction to Trigonometry Question Bank MCQs - Introduction to Trigonometry

  • question_answer
    \[\frac{1+{{\tan }^{2}}A}{1+{{\cot }^{2}}A}\]is equal to:

    A) \[{{\sec }^{2}}A\]

    B) \[-1\]

    C) \[{{\cot }^{2}}A\]

    D) \[{{\tan }^{2}}A\]

    Correct Answer: D

    Solution :

    [d] \[\frac{1+{{\tan }^{2}}A}{1+{{\cot }^{2}}A}=\frac{{{\sec }^{2}}A}{\cos e{{c}^{2}}A}=\frac{1}{{{\cos }^{2}}A}\times {{\sin }^{2}}A={{\tan }^{2}}A\]


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