A) \[\sec A\]
B) \[\sin A\]
C) \[\text{cosec A}\]
D) \[\text{cos A}\]
Correct Answer: D
Solution :
| [d] \[(\sec A+\tan A)\,\,(1-\sin A)\] |
| \[=\left( \frac{1}{\cos A}+\frac{\sin A}{\cos A} \right)\,\,\,(1-\sin A)=\frac{(1+\sin A)(1-\sin A)}{\cos A}\] |
| \[=\frac{1-{{\sin }^{2}}A}{\cos A}=\frac{{{\cos }^{2}}A}{\cos A}\] \[[{{\sin }^{2}}\theta +{{\cos }^{2}}\theta =1]\] |
| \[=\cos A.\] |
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