A) 6 m/s
B) 4 m/s
C) 5.6m/s
D) 6.5m/s
Correct Answer: B
Solution :
| [b] Time travel to cover 24 m with speed 4 m/s, |
| \[{{t}_{1}}=\frac{24}{4}=6\operatorname{s}\] |
| Time travel to cover 32 m with speed 8 m/s, |
| \[{{t}_{2}}=\frac{32}{8}=4\operatorname{s}\] |
| \[\operatorname{Average} speed=\frac{Total distance}{Total time}=\frac{24+32}{{{t}_{1}}+{{t}_{2}}}\] |
| \[=\frac{56}{6+4}=5.6\operatorname{m}/s\] |
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