A) \[-10.4\ m/{{s}^{2}}\]
B) \[10.4\ m/{{s}^{2}}\]
C) \[1.04\ m/{{s}^{2}}\]
D) \[-1.04\ m/{{s}^{2}}\]
Correct Answer: A
Solution :
| [a] Given, u = 60 km/h = \[60\frac{5}{18}\operatorname{m}/s=\frac{50}{3}\operatorname{m}/s,\] |
| \[t=1.6\ s,v=0\] |
| \[\therefore \] Average acceleration, |
| \[a=\frac{v-u}{t}=\frac{0-\frac{50}{3}}{1.6}=\frac{-50}{3\times 1.6}\] |
| \[=\frac{-100}{3\times 3.2}=\frac{-1000}{96}\] |
| \[=-10.4\operatorname{m}/{{s}^{2}}\] |
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