A) \[2.4\text{ }m/{{s}^{2}}\]
B) \[1.2\text{ }m/{{s}^{2}}\]
C) \[2\text{ }m/{{s}^{2}}\]
D) \[5.2\text{ }m/{{s}^{2}}\]
Correct Answer: B
Solution :
[b] \[a=\frac{dv}{dt}\] |
The increase in speed = (30 -12) =18 m/s |
Then, \[a=\frac{18}{15}=1.2\operatorname{m}/{{s}^{2}}\] |
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