A) \[\frac{2}{3}\]
B) \[\frac{4}{9}\]
C) \[\frac{6}{11}\]
D) \[\frac{7}{11}\]
Correct Answer: D
Solution :
| Since u = 0, so using, |
| \[{{s}_{n}}=u+a\ \left( n-\frac{1}{2} \right),\] |
| \[{{s}_{1}}=0+\frac{7a}{2}=\frac{7a}{2}\] |
| \[{{s}_{2}}=0+\frac{11a}{2}=\frac{11a}{2}\] |
| \[\therefore \frac{{{s}_{1}}}{{{s}_{2}}}=\frac{7}{11}\] |
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