A) zero
B) \[\pi r\]
C) 2r
D) 2\[\pi r\]
Correct Answer: C
Solution :
| [c] Given, after half the circle, the particle will reach the diametrically opposite point i.e., from point A to point B. And we know displacement is shortest path between initial and final point. |
| \[\therefore \] Displacement after half circle |
| = AB = AO + OB |
 |
| \[=r+r=2r\ \ [\therefore \operatorname{Given},OA\ \operatorname{and}\ OB=r]\] |
| Hence, the displacement after half circle is 2r. |
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