A) 4.71 m/s and 47.1 m/s
B) 4.71 m/s and 1.41 m/s
C) 1.41 m/s and 4.71 m/s
D) 1.41 m/s and 1.41 m/s
Correct Answer: B
Solution :
[b] Distance \[=\frac{3}{4}\times 2\pi r\] |
\[h=\frac{3}{4}\times 2\times \frac{22}{7}\times 10=47.10\operatorname{m}\] |
Displacement =\[\sqrt{2r}=10\sqrt{2}\] |
\[\therefore \operatorname{Speed}=\frac{Distance}{Time}=\frac{47.10}{10}=4.71\ m{{s}^{-1}}\] |
\[\therefore \operatorname{Velocity}=\frac{Displacement}{Time}=\frac{10\sqrt{2}}{10}=1.41\ {{\operatorname{ms}}^{-1}}\] |
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