A) \[8:3\]
B) \[3:8\]
C) \[8:9\]
D) \[9:8\]
Correct Answer: C
Solution :
[c] Let distance =d |
Time taken upstream \[=\frac{d}{15-5}=\frac{d}{10}\] |
Time taken downstream \[=\frac{d}{15+5}=\frac{d}{20}\] |
Hence, average speed |
\[=\frac{2d}{\frac{d}{10}+\frac{d}{20}}=\frac{2d\times 20}{3d}=\frac{40}{3}km/hr\] |
Ratio \[=\frac{40}{3}:15=40:45=8:9\] |
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